In a coffee cup calorimeter, are 75.0 mL of 1.1 M HCl AgNO3 50.0 mL of 2.3 M and?

In a coffee cup calorimeter, 75.0 mL AgNO3 1.1M HCl and 50.0 ml of 2.3 M are mixed to form silver chloride. The two solutions are initially at 22.6 ° C and the finishing temperature is 23.4 ° C. Calculate heat of reaction per mole of silver chloride formed (KJ mol /).

1:01:01 This is called a reaction, these figures refer to total ratio of the most small coefficients in the balanced equation. Ag (+) + Cl (-) —> AgCl In this case, it would be a 1 in each reactant and product, at 1:01:01, as mentioned. We also have an equation that relates these properties of the energy / heat, mass and temperature. And this equation is: q = m * sh * DELTA.T (Q) = amount of heat absorbed by water (generated by the reaction) (m) = mass of water, the material temperature changes (sh) = 4.18 J / g * K (DT) = Change in temperature, water = 23.4 to 22.6 = 0.8 to obtain (q), we need to know the mass of water flowing temperature change. To do this we assume that the density of solutions is equal to the density of water, or close enough such that we can treat them as equals …. have a density of 1.0 g / cc (grams per centimeter cubic). We know that the volume of each component, and we know that 1 cc = 1 ml, then … m1 * V1 = = d (1.0 mg / mL) = 75.0 mL 75.0 g * m2 * V2 = (1.0 grams per mL) = 50.0 g = 50.0 ml * H2O = total mass M M1 M2 + = + = 125.0 75.0g 50.0g gq = 125 * 4.18 J / g * C * 0.8 = 418 AD That is the amount of energy absorbed as heat by the water, which should be the amount of heat generated by the reaction. Now we determine the number of moles of product formed. We can see in the chemical above equation that the amount of silver chloride formed is equal to the amount of money ionic reaction. Therefore, if both are present in different quantities, we set the lower amount to react until either party, which only means that the same amount of other reagents in fact respond, the rest will be surplus. mol of Ag (+) = mol AgNO3 M * V = (1.1 mol / L) * (0.0750 L) = 0.0825 mol of Cl (-) HCl = V * M = (2.3 mol / L) * (0.050 L) = 0.115 Therefore , Only 0.0825 moles of all the 0.115 moles of Cl (-) will react, and therefore 0.0825 moles of AgCl is formed. Heat of reaction = = ΔHrxn (q) / mol AgCl = 418 J / mol = 0.0825 5.07×10 ³ J = (5.07 kJ / mol) AgCl